A 2000 acre, 15 ft thick, 15% porosity waterflood reservoir with a Sgi of 20% and a producer/injector distance of 330 ft is started on injection.
How much water volume (barrels) must be injected until interference within a single 5-spot pattern?
Wii = [3.14159/(2*5.615)](330^2)15(0.15)(.2) = 13,710 bbl (B)
How much total volume to pattern's fill-up?
Wif = (2/5.615)](330^2)15(0.15)(.2) = 17,455 bbl (B)
Hi David,
ReplyDeleteWhen you calculated the water volume must be injected until interference within a 5-spot pattern,
Why you divided by (2*5.615)? I understand all the other numbers, but I don't understand what 2 means.
Thanks for your explanation.
And for the total volume to patter's fill-up, can you also explain how you calculated?
Thanks a lot!
Wendy
Do you see the reference in the Guidebook for 14 WFL 5 in the variable box? It has the SPE reference used, which is TS3 118-120 & 190-200. Do you have TS3?
DeleteMy thinking is that if you don't have TS3 I would look over the Updated reference and see what they say about this subject. If nothing, I would just look over the Guidebook equations for how the variables relate to each other in case. But I wouldn't buy the text to study the subject in detail because I think it's pretty obscure. I would know everything in the HB related to the subject; this stuff would be a good word problem.
DeleteHi David,
ReplyDeleteThanks for your reply! I have the PE handbook 7 volumes and the guidebook from you. What is TS3?
Now I think I understand how to calculate the total volume patter's fill up. The area of the single 5 -spot is a square, the area of the square is 330^2*2, this make senses now.
I will further look into how to calculate the water volume for interference.
Thanks!
Wenli
TS is Textbook Series. ts3 isn't used much, so I wouldn't wory too much if you don't have it. It's only if you want the deep answers you were asking and I would let the HS & provided reference set the bounds on this wort of thing.
Delete