5,000' of 14.00 lb/ft drillpipe
(adjusted weight is 1.1 times nominal) and 100 ft of 120 lb/ft drill collars are pulled dry. Fluid volume change?
14 ppf(1.1)5,000' = 77M lb.
120 ppf(100') = 12M lb.
77M+12M lb = 89 M lb/(490 lb/cf*5.615 cf/bbl) = 32 bbl (A).
The trick on this one is to use adjusted weight if given; never use OD & ID unless you don't have adjusted weight. In that case use the adjusted weight / density equation (see 1 RIG 1). Regardless, know how to do this sort of problem fast.
During the exam, locate the needed constants of 490 lbm/cf & 5.615 cf/bbl are in the new Reference Guide
(provided with the exam) on page 190 of chapter 7. Practice finding these numbers quickly.
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