5,000' of 14.00 lb/ft drillpipe
(adjusted weight is 1.1 times nominal) and 100 ft of 120 lb/ft drill collars are pulled dry. Fluid volume change?
14 ppf(1.1)5,000' = 77M lb.
120 ppf(100') = 12M lb.
89 M lb/(2751 lb/bbl) = 32 bbl (A).
The trick on this one is to use adjusted weight whenever given; never use OD & ID unless you don't have adjusted weight. Then use the adjusted weight / density equation (see 1 RIG 1). Know how to do this sort of problem fast.
Note some prefer to use 490 lbm/cf x 5.615 cf/bbl rather than 2,751 lb/bbl that I use here since they have 490 & & 5.615 memorized.
Hi, David. The input that you used here is for problem #20 in 2016, not 2017. Problem #20 in 2017 has different depths (7000 ft and 500 ft) and answer is 61 bbl (option A).
ReplyDeleteWhy wouldn't you use displacement here (0.0051 for DP, 0.0438 for DC) which equates to 57.6bbl?
ReplyDelete