Directional Drilling: 2016 #4

What is the MD of the Problem #3 well if at a TVD of 6,000 ft drops at 2 deg/100 ft until vertical?

This is easy since in #3 build was 895 ft (MD) at 3 deg/100 ft. If the well then drops at the same rate, we merely add this MD to the sequence: 6,198 + 895 = 7,093 ft (C).